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15/09/2021 10:12 am
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If E and G respectively denote energy and gravitational constant, then E/G has the dimensions of :
(1) [M2] [L-1] [T0]
(2) [M] [L-1] [T -1]
(3) [M] [L0] [T0]
(4) [M2] [L-2] [T -1]
1 Answer
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15/09/2021 10:16 am
Correct answer: (1) [M2] [L-1] [T0]
Explanation:
E = energy = [ML2T-2]
G = Gravitational constant = [M-1L3T-2]
So \(\frac{E}{G}\) = \(\frac{[E]}{[G]}\)
= \(\frac{ML^2T^{-2}}{M^{-1}L^3T^{-2}}\) = [M2] [L-1] [T0]