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13/09/2021 10:41 am
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An inductor of inductance L, a capacitor of capacitance C and a resistor of resistance 'R' are connected in series to an ac source of potential difference 'V' volts as shown in figure.
Potential difference across L, C and R is 40 V, 10 V and 40 V, respectively. The amplitude of current flowing through LCR series circuit is 10√2 A. The impedance of the circuit is
(1) 4√2Ω
(2) 5/√2Ω
(3) 4Ω
(4) 5Ω
1 Answer
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13/09/2021 10:45 am
Correct option: (4) 5 Ω
I0 = 10√2A
IRMS = \(\frac{I_0}{\sqrt{2}}\)
= 10 A
VRMS = \(\sqrt{V_R^2 + (V_L - V_C)^2}\)
= \(\sqrt{(40)^2 + (40 - 10)^2}\)
= 50V
Z = \(\frac{V_{RMS}}{I_{RMS}}\)
= 50V/10V
= 5 Ω
This post was modified 3 years ago 3 times by admin