Notifications
Clear all
0
14/09/2021 11:00 am
Topic starter
A spring is stretched by 5 cm by a force 10 N. The time period of the oscillations when a mass of 2 kg is suspended by it is:
(1) 0.0628 s
(2) 6.28 s
(3) 3.14 s
(4) 0.628 s
1 Answer
0
14/09/2021 11:10 am
Correct answer: (4) 0.628 s
Explanation:
F = kx
10 = k(5 × 10–2)
k = \(\frac{10}{5 \times 10^{-2}}\) = 2 x 102
= 200 N/m
Now T = 2π\(\sqrt{\frac{m}{k}}\)
= 2π\(\sqrt{\frac{2}{200}}\) = \(\frac{2 \pi}{10}\)
= 0.628 s