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13/09/2021 12:35 pm
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A radioactive nucleus AZX undergoes spontaneous decay in the sequence
AZX → z-1B → z-3C → z-2D, where Z is the atomic number of element X. The possible decay particles in the sequence are:
(1) α, β-, β+
(2) α, β+, β-
(3) β+, α, β-
(4) β-, α, β+
1 Answer
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13/09/2021 12:50 pm
Correct answer: (3) β+, α, β-
Explanation:
AZX + β+→ z-1B + α → z-3C + β-→ z-2D
β+ decreases atomic number by 1
α decreases atomic number by 2
β- increases atomic number by 2