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14/09/2021 10:27 am
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A nucleus with mass number 240 breaks into two fragments each of mass number 120, the binding energy per nucleon of unfragmented nuclei is 7.6 MeV while that of fragments is 8.5 MeV. The total gain in the Binding Energy in the process is :
(1) 0.9 MeV
(2) 9.4 MeV
(3) 804 MeV
(4) 216 MeV
1 Answer
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14/09/2021 10:30 am
Correct answer: (4) 216 MeV
Explanation:
X20 → Y120 + Z120
given binding energy per nucleon of X, Y & Z are 7.6 MeV, 8.5 MeV & 8.5 MeV respectively.
Gain in binding energy is :
Q = Binding Energy of products – Binding energy of reactants
= (120 × 8.5 × 2) – (240 × 7.6) MeV
= 216 MeV