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13/09/2021 4:26 pm
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A body is executing simple harmonic motion with frequency 'n', the frequency of its potential energy is
(1) n
(2) 2n
(3) 3n
(4) 4n
This topic was modified 3 years ago by admin
1 Answer
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13/09/2021 4:33 pm
Answer is: (2) 2n
Displacement Equation of simple harmonic motion of frequency 'n'
x = Asin(ωt) = Asin(2πnt)
P.E (Potential Energy) U = \(\frac{1}{2}kx^2\)
= \(\frac{1}{2}KA^2\; sin^2\)(2πnt)
= \(\frac{1}{2}KA^2 \Big[\frac{1-cos(2 \pi(2n)t)}{2}\Big]\)
So, Frequency of Potential Energy (P.E) = 2n
This post was modified 3 years ago by admin