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13/06/2021 12:11 pm
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Rationalise the denominator of \(\frac{1}{7+3 \sqrt3}\).
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13/06/2021 12:15 pm
Given, \(\frac{1}{7+3\sqrt3}\)
= \(\frac{1}{7+3\sqrt3} \times \) \(\frac{7-3\sqrt3}{7-3\sqrt3} \)
= \(\frac{7-3\sqrt3}{49-27} \)
= \(\frac{7-3\sqrt3}{22} \)