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Two ores A and B were taken. On heating, ore A gives CO2 whereas, ore B gives SO2. What steps will you take to convert them into metals?

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Two ores A and B were taken. On heating, ore A gives CO2 whereas, ore B gives SO2. What steps will you take to convert them into metals?

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Since ore ‘A’ gives CO2 and ore ‘B’ gives SO2. Therefore, A is metal carbonate ore and ‘B’ is metal sulphide ore.

Metal carbonate on heating gives ‘MO’.

‘MO’, on reduction with coke gives metal and carbon monoxide.

MO + C + heat → M + CO

Metal ‘M’ is obtained which can be purified by electrolytic refining.

Metal sulphide is heated in presence of oxygen to form metal oxide and SO2.

2MS(s) + 3O2(g) + Roasting → 2MO(s) + 2SO2(g)

Metal sulphide reacts with metal oxide to form impure metal and SO2.

MS + 2MO → 3M + SO2

MO can also be reduced with carbon to form metal. The metal ‘M’ from ore ‘B’ is obtained.

MO + C(s) + heat → M(s) + CO(g)

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