Two ores A and B were taken. On heating, ore A gives CO2 whereas, ore B gives SO2. What steps will you take to convert them into metals?
Two ores A and B were taken. On heating, ore A gives CO2 whereas, ore B gives SO2. What steps will you take to convert them into metals?
Since ore ‘A’ gives CO2 and ore ‘B’ gives SO2. Therefore, A is metal carbonate ore and ‘B’ is metal sulphide ore.
Metal carbonate on heating gives ‘MO’.
‘MO’, on reduction with coke gives metal and carbon monoxide.
MO + C + heat → M + CO
Metal ‘M’ is obtained which can be purified by electrolytic refining.
Metal sulphide is heated in presence of oxygen to form metal oxide and SO2.
2MS(s) + 3O2(g) + Roasting → 2MO(s) + 2SO2(g)
Metal sulphide reacts with metal oxide to form impure metal and SO2.
MS + 2MO → 3M + SO2
MO can also be reduced with carbon to form metal. The metal ‘M’ from ore ‘B’ is obtained.
MO + C(s) + heat → M(s) + CO(g)
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