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Tangent and normal at P(2, -4) to parabola y^2 = 8x meet directrix at A and B. Q(a, b) is such that APBQ is a square. Find 2a + b.

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Tangent and normal at P(2, -4) to parabola y2 = 8x meet directrix at A and B. Q(a, b) is such that APBQ is a square. Find 2a + b.

(a) -12

(b) -16

(c) -20

(d) -18

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Correct answer: (b) -16

Explanation:

y2  = 8x

⇒ a = 2

Tangent equation -4y = 4(x + 2)

⇒ x + y + 2 = 0

Normal: x - y + 6 = 0

Directrix x + 2 = 0

A = (-2, 0), B = (-2, -8)

Because, mid-point AB is (-2, -4)

So, Q = (-6, -4)

2a + b = -16

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