If x φ(x) = ∫_5^x (3t^2  2φ'(t))dt, x > 2, and φ(0) = 4, then φ(2) is ................
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08/02/2022 2:56 pm
x φ(x) = \(\int_5^x\)(3t^{2}  2φ'(t))dt
xφ(x) = x^{3} 125  2[φ(x)  φ(5)]
xφ(x) = x^{3} 125  2φ(x)  2φ(5)
φ(0) = 4 ⇒ φ(5) = \(\frac{133}{2}\)
φ(x) = \(\frac{x^3 + 8}{x+2}\)
φ(2) = 4
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