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27/12/2021 12:48 pm
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If sum of distances of point P from (0, 0) (0, 1) (1, 0), (1, 1) = 18 Locus is at circle of diameter. find d2.
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27/12/2021 1:31 pm
x2 + y2 + x2(y -1)2 + y2 + (x -1)2 + (y -1)2 = 18
x2 + y2 + x2 + y2 - 2y + 1 + x2 - 2x + 1 + y2 + x2 - 2x + 1 + y2 - 2y + 1 = 18
4x2 + 4y2 - 4x - 4y + 4 = 18
x2 + 4y2 - 4x - 4y - 14 = 0
x2 + y2 - x - y - \(\frac{7}{2}\) = 0
r = \(\sqrt{(\frac{1}{2})^2 - (\frac{1}{2})^2 + \frac{7}{2}}\)
= 2
d = 4
d2 = 16
This post was modified 3 years ago 2 times by Reyana09