Find y(π) if y(0) = 7 and dy/dx = 2(y - 2 sin x - 10)x + 2 cos x
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05/01/2022 1:53 pm
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Find y(π) if y(0) = 7 and dy/dx = 2(y - 2 sin x - 10)x + 2 cos x
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05/01/2022 2:00 pm
\(\frac{dy}{dx}\) = 2(y - 2 sin x - 10)x + 2 cos x
\(\frac{dy}{dx}\) - 2 cos x = 2(y - 2 sin x - 10)x
\(\frac{d}{dx}\)( \(\frac{y -2 sin \ x - 10}{y -2\;sin \;x - 10}\)) = 2x
⇒ ∫d[/latex]( \(\frac{y -2 sin \ x - 10}{y -2\;sin \;x - 10}\)) = ∫2x dx
⇒ log |y - 2 sin x - 10| = x2 + C
At x = 0, y = 7
⇒ log |7 - 0 - 10| = 0 + C
⇒ C = log 3
At x = π
⇒ log |y - 2 sin π - 10| = π2 + log 3
⇒ log \(\frac{(y -10)}{2}\) = π2
⇒ y(π) = 3eπ2 + 10
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