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cosec 18° is a root of the equation

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cosec 18° is a root of the equation

(1) x2 + 2x – 4 = 0

(2) 4x2 + 2x – 1 = 0

(3) x2 – 2x + 4 = 0

(4) x2 – 2x – 4 = 0

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Correct answer: (4) x2 – 2x – 4 = 0

Explanation:

cosec 18° = \(\frac{1}{sin 18°}\)

= \(\frac{4}{\sqrt 5 - 1}\) = \(\sqrt 5 + 1\)

Let cosec 18° = x = \(\sqrt 5 + 1\)

⇒ x - 1 = √5

Squaring both sides, we get

x2 - 2x + 1 = 5

⇒ x2 – 2x – 4 = 0

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