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A vertical pole fixed to the horizontal ground is divided in the ratio 3 : 7 by a mark on it with lower part shorter than the upper part.

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A vertical pole fixed to the horizontal ground is divided in the ratio 3 : 7 by a mark on it with lower part shorter than the upper part. If the two parts subtend equal angles at a point on the ground 18 m away from the base of the pole, then the height of the pole (in meters) is :

(1) 12√15

(2) 12√10

(3) 8√10

(4) 6√10

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Correct answer: (2) 12√10

Explanation:

Let height of pole = 10ℓ

tanα = \(\frac{3ℓ}{18}\) = \(\frac{ℓ}{6}\)

tan2α = \(\frac{10ℓ}{18}\)

\(\frac{2 tanα}{1 - tan^2α}\) = \(\frac{10ℓ}{18}\)

use tanα = \(\frac{ℓ}{6}\) ⇒ ℓ = \(\sqrt{\frac{72}{5}}\)

height of pole = 10ℓ = 12√10

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