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In Figure, if AB CD, EF ⊥ CD and GED = 126°, find AGE, GEF and FGE.

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In Figure, if AB CD, EF ⊥ CD and GED = 126°, find AGE, GEF and FGE.

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Since AB CD, GE is a transversal.

It is given that GED = 126°

GED = AGE = 126° (As they are alternate interior angles)

GED = GEF +FED

As EF⊥ CD, FED = 90°

∴ GED = GEF+90°

GEF = 126° – 90° = 36°

Again, FGE + GED = 180° (Transversal)

Putting the value of GED = 126° we get,

FGE = 54°

AGE = 126°

GEF = 36° and

FGE = 54°

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