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Two lenses A and B have focal lengths of +20 cm and, -10 cm, respectively. (a) What is the nature of lens A and lens B? (b) What is the power of lens A and lens B?

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Two lenses A and B have focal lengths of +20 cm and, -10 cm, respectively.

(a) What is the nature of lens A and lens B?

(b) What is the power of lens A and lens B?

(c) What is the power of combination if lenses A and B are held close together?

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\(f_A\) = +20 cm = +0.2 m

\(f_B\) = -10 cm = -0.1 m

(a) Lens A is a convex lens (positive focal length) and lens B is a concave lens (negative focal length).

(b) \(P_A\) = \(\frac{1}{f_A}\) = \(\frac{1}{+0.2}\)

= +5D

\(P_B\) = \(\frac{1}{f_B}\) = \(\frac{1}{-0.1}\)

= -10D

(c) Power of combination

P = \(P_A\) + \(P_B\)

= +5D + (-10D)

= -5D

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