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How far should an object be placed from the pole of a converging mirror of focal length 20 cm to form a real image of the size exactly 1/4 th the size of the object?

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How far should an object be placed from the pole of a converging mirror of focal length 20 cm to form a real image of the size exactly 1/4 th the size of the object?

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f = -20 cm, m = -\(\frac{1}{4}\)(real image)

We know that

m = -\(\frac{v}{u}\)

\(-\frac{1}{4}\) = -\(\frac{v}{u}\)

u = 4v

So,

\(\frac{1}{v}\) + \(\frac{1}{u}\) = \(\frac{1}{f}\)

\(\frac{1}{v}\) + \(\frac{1}{4v}\) = \(\frac{1}{-20}\)

\(\frac{5}{4v}\) = -\(\frac{1}{20}\)

v = -\(\frac{100}{4}\) = -25 cm

∴ u = 4v

u = 4 x (-25)

= -100 cm

The object should be placed 100 cm to the left of the mirror.

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