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Determine how far an object must be placed in front of a converging lens of focal length 10 cm in order to produce an erect (upright) image of linear magnification 4.

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Determine how far an object must be placed in front of a converging lens of focal length 10 cm in order to produce an erect (upright) image of linear magnification 4.

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f = 10 cm

m = +4 (upright image)

m = \(\frac{v}{u}\) = 4

v = 4u

\(\frac{1}{v}\) - \(\frac{1}{u}\) = \(\frac{1}{f}\)

\(\frac{1}{4u}\) - \(\frac{1}{u}\) = \(\frac{1}{10}\)

\(\frac{-3}{4u}\) = \(\frac{1}{10}\)

u = -7.5 cm

The object must be placed 7.5 cm in front of the converging lens.

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