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Light Reflection and Refraction
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18/08/2021 11:54 am
Topic starter
At what distance should an object be placed from a convex lens of focal length 18 cm to obtain an image at 24 cm from it on the other side? What will be the magnification produced in this case?
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18/08/2021 12:03 pm
f = 18 cm
v = 24 cm
\(\frac{1}{v}\) - \(\frac{1}{u}\) = \(\frac{1}{f}\)
\(\frac{1}{24}\) - \(\frac{1}{u}\)= \(\frac{1}{18}\)
\(\frac{1}{u}\) = \(\frac{1}{24}\) - \(\frac{1}{18}\)
\(\frac{1}{u}\) = \(\frac{3 - 4}{72}\)
= \(\frac{-1}{72}\)
u = -72 cm
m = \(\frac{v}{u}\) = \(\frac{24}{-72}\)
= -\(\frac{1}{3}\)