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Light Reflection and Refraction
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13/08/2021 1:13 pm
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An object is placed at a distance of 6 cm from a convex mirror of focal length 12 cm. Find the position and nature of the image.
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13/08/2021 1:17 pm
u = -6 cm, f = 12 cm, v = ?
We know that
\(\frac{1}{v}\) + \(\frac{1}{u}\) = \(\frac{1}{f}\)
⇒ \(\frac{1}{v}\) + \(\frac{1}{-6}\) = \(\frac{1}{12}\)
⇒ \(\frac{1}{v}\) = \(\frac{1}{12}\) + \(\frac{1}{6}\) = \(\frac{3}{12}\)
v = \(\frac{1}{4}\)cm
∴ v = 4 cm
Image will be formed 4 cm behind the mirror.
Since the images is formed behind the convex mirror, it is virtual and erect.