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Light Reflection and Refraction
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20/08/2021 12:55 pm
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An object is placed at a distance of 4 cm from a concave lens of focal length 12 cm. Find the position and nature of the image.
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20/08/2021 12:58 pm
u = -4 cm
f = -12 cm
\(\frac{1}{v}\) - \(\frac{1}{u}\) = \(\frac{1}{f}\)
\(\frac{1}{v}\) - \(\frac{1}{-4}\) = \(\frac{1}{-12}\)
\(\frac{1}{v}\) = -\(\frac{1}{12}\) - \(\frac{1}{4}\)
\(\frac{1}{v}\) = \(\frac{-4}{12}\)
v = -3 cm
Image is formed 3 cm infront of the concave lens.
Image is virtual and erect.