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Light Reflection and Refraction
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13/08/2021 12:57 pm
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An object is kept at a distance of 5 cm in front of a convex mirror of focal length 10 cm. Calculate the position and magnification of the image and state its nature.
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13/08/2021 1:02 pm
u = -5 cm, f = 10 cm
We know that
\(\frac{1}{v}\) + \(\frac{1}{u}\) = \(\frac{1}{f}\)
⇒ \(\frac{1}{v}\) + \(\frac{1}{-5}\) = \(\frac{1}{10}\)
⇒ \(\frac{1}{v}\) = \(\frac{1}{10}\) + \(\frac{1}{5}\) = \(\frac{3}{10}\)
∴ v = \(\frac{10}{3}\)cm = 3.33cm
The position of the image is 3.33 cm behind the convex mirror.
Magnification, m = \(\frac{v}{u}\)
= \(\frac{-3.33}{-5}\) = 0.66
The image is virtual and erect.