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An object 60 cm from a lens gives a virtual image at a distance of 20 cm in front of the lens. What is the focal length of the lens?

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An object 60 cm from a lens gives a virtual image at a distance of 20 cm in front of the lens. What is the focal length of the lens? Is the lens converging or diverging? Give reasons for your answer.

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u = -60 cm

v = -20 cm (Virtual image)

\(\frac{1}{f}\) = \(\frac{1}{v}\) - \(\frac{1}{u}\)

\(\frac{1}{f}\) = \(\frac{1}{-20}\) - \(\frac{1}{-60}\)

= \(\frac{-2}{60}\)

f = -30 cm

The lens is diverging because the focal length is negative.

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