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Light Reflection and Refraction
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17/08/2021 3:42 pm
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A small object is so placed in front of a convex lens of 5 cm focal length that a virtual image is formed at a distance of 25 cm. Find the magnification.
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17/08/2021 3:46 pm
f = 5 cm
v = -25 cm (virtual image)
\(\frac{1}{v}\) - \(\frac{1}{u}\) = \(\frac{1}{f}\)
\(\frac{1}{-25}\) - \(\frac{1}{u}\) = \(\frac{1}{5}\)
\(\frac{1}{u}\) = -\(\frac{1}{25}\) - \(\frac{1}{5}\)
= -\(\frac{6}{25}\)
u = -\(\frac{25}{6}\)
Magnification, m = \(\frac{v}{u}\) = \(\frac{-25}{\frac{-25}{6}}\)
= +6