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A large concave mirror has a radius of curvature of 1.5 m. A person stands 10 m in front of the mirror. Where is the person’s image?

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A large concave mirror has a radius of curvature of 1.5 m. A person stands 10 m in front of the mirror. Where is the person’s image?

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R = -1.5 cm (concave mirror)

u = -10m

f = \(\frac{R}{2}\) =\(\frac{-1.5}{2}\)

= -0.75 cm

We know

\(\frac{1}{v}\) + \(\frac{1}{u}\) = \(\frac{1}{f}\)

⇒ \(\frac{1}{v}\) + \(\frac{1}{-10}\) = \(\frac{1}{-0.75}\)

⇒ \(\frac{1}{v}\) = \(\frac{1}{10}\) - \(\frac{1}{0.75}\)

= \(\frac{1}{10}\) - \(\frac{100}{75}\)

= \(\frac{1}{10}\) - \(\frac{4}{3}\)

= \(\frac{3 - 40}{30}\) = - \(\frac{37}{30}\)

v = - \(\frac{37}{30}\) = -0.81 m

The person's image will be 0.81 m in front of concave mirror.

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