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Light Reflection and Refraction
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18/08/2021 12:24 pm
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A convex lens of focal length 0.10 m is used to form a magnified image of an object of height 5 mm placed at a distance of 0.08 m from the lens. Calculate the position, nature and size of the image.
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18/08/2021 12:31 pm
f = 0.10 m
\(h_1\) = 5 mm = 0.005 m
u = -0.08 m
\(\frac{1}{v}\) - \(\frac{1}{u}\) = \(\frac{1}{f}\)
\(\frac{1}{v}\) - \(\frac{1}{-0.08}\) = \(\frac{1}{0.10}\)
\(\frac{1}{v}\) = \(\frac{1}{0.10}\) - \(\frac{1}{0.08}\)
v = -0.4 m
Image is formed 0.40 m in front of the convex lens.
m = \(\frac{v}{u}\) = \(\frac{h_2}{h_1}\)
\(\frac{-0.4}{-0.08}\) = \(\frac{h_2}{0.005}\)
\(h_2\) = 0.025 m = 25 mm
Size of image is 25 mm
Image is virtual and erect.