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A converging mirror forms a real image of height 4 cm of an object of height 1 cm placed 20 cm away from the mirror : (i) Calculate the image distance. (ii) What is the focal length of the mirror?

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A converging mirror forms a real image of height 4 cm of an object of height 1 cm placed 20 cm away from the mirror :

(i) Calculate the image distance.

(ii) What is the focal length of the mirror?

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\(h_2\) = -4 cm (real image)

\(h_1\) = 1 cm

u = -20 cm

v = ?

(i) m = \(\frac{h_2}{h_1}\) = -\(\frac{v}{u}\)

⇒ \(\frac{-4}{1}\) = -\(\frac{v}{-20}\)

⇒ v = -80 cm

Image forms in front of the concave mirror.

(ii) f = ?

\(\frac{1}{v}\) + \(\frac{1}{u}\) = \(\frac{1}{f}\)

\(\frac{1}{f}\) = \(-\frac{1}{80}\) - \(\frac{1}{20}\)

= \(\frac{-1 - 4}{80}\) = \(-\frac{5}{80}\)

f = -16 cm

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