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A bright object 50 mm high stands on the axis of a concave mirror of focal length 100 mm and at a distance of 300 mm from the concave mirror. How big will the image be?

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A bright object 50 mm high stands on the axis of a concave mirror of focal length 100 mm and at a distance of 300 mm from the concave mirror. How big will the image be?

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\(h_1\) = 50 mm, f = 100 mm, u = 300 mm,

\(h_1\) = ?

We have

\(\frac{1}{v}\) + \(\frac{1}{u}\) = \(\frac{1}{f}\)

\(\frac{1}{v}\) + \(\frac{1}{-300}\) = \(\frac{1}{-100}\)

\(\frac{1}{v}\) = \(\frac{1}{300}\) - \(\frac{1}{100}\)

\(\frac{1}{v}\) = \(\frac{-200}{30000}\)

\(\frac{1}{v}\) = \(\frac{-2}{300}\)

v = -150 mm

m = -\(\frac{v}{u}\) = \(\frac{h_2}{h_1}\)

= \(\frac{-150}{-300}\) = \(\frac{h_2}{50}\)

The image will be 25 mm high.

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