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Light Reflection and Refraction
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20/08/2021 1:34 pm
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A 2.0 cm tall object is placed 40 cm from a diverging lens of focal length 15 cm. Find the position and size of the image.
1 Answer
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20/08/2021 1:38 pm
\(h_1\) = 2 cm
u = -40 cm
f = -15 cm
\(\frac{1}{v}\) - \(\frac{1}{u}\) = \(\frac{1}{f}\)
\(\frac{1}{v}\) - \(\frac{1}{-40}\) = \(\frac{1}{-15}\)
\(\frac{1}{v}\) = -\(\frac{1}{15}\) - \(\frac{1}{40}\)
\(\frac{1}{v}\) = \(\frac{-11}{120}\)
v = -10.90 cm
m = \(\frac{v}{u}\) = \(\frac{h_2}{h_1}\)
= \(\frac{-10.90}{-40}\) = \(\frac{h_2}{2}\)
\(h_2\) = 0.54 cm