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12/12/2021 2:24 pm
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The purity of H2O2 in a given sample is 85%. Calculate the weight of impure sample of H2O2 which requires 10 mL of M/5 KMnO4 solution in titration in acidic medium
(a) 2 g
(b) 0.2 g
(c) 0.17 g
(d) 0.15 g
1 Answer
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12/12/2021 2:30 pm
Correct answer: (b) 0.2 g
Explanation:
mEq of KMnO4- ≡ mEq of H2O2
10 x \(\frac{M}{5}\)x 5 ≡ mEq of H2O2
10 mEq ≡ mEq of H2O2
Weight of H2O2 = 10 x \(10^{-3} \times\frac{34}{2}\) x 0.17
= 0.2 g
Weight of impure H2O2
= \(\frac{100}{85}\)x 0.17 = 0.2 g