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08/12/2021 11:12 am
Topic starter
34 g of H2O2 is present in 1120 mL of solution. This solution is called
(a) 10 vol solution
(b) 20 vol solution
(c) 34 vol solution
(d) 32 vol solution
1 Answer
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08/12/2021 11:16 am
Correct answer: (a) 10 vol solution
Explanation:
N = \(\frac{W_2 \times 1000}{Ew_2 \times VmL}\)
= \(\frac{34 \times 1000}{17 \times 1120}\) = \(\frac{200}{12}\)
1N of H2O2 = 5.6 vol strength
\(\frac{200}{12}\)N of H2O2 = 5.6 x \(\frac{200}{12}\)
= 10 vol strength