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11/12/2021 2:18 pm
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100 mL of 0.01 M KMnO4 oxidises 100 mL H2O2 in acidic medium. Volume of the same KMnO4 required in alkaline medium to oxidise 100 mL of the same H2O2 will be (MnO4- changes to Mn2+ in acidic medium and to MnO2 in alkaline medium)
(a) \(\frac{100}{3}\)mL
(b) \(\frac{500}{3}\)mL
(c) \(\frac{300}{5}\)mL
(d) None
1 Answer
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11/12/2021 2:23 pm
Correct answer: (b) \(\frac{500}{3}\)mL
Explanation:
MnO4- + 5e- → Mn2+ (acidic)
MnO4- + 3e- → MnO2 (basic)
100 mL H2O2 ≡ 100 x 5N
MnO4- ≡ V x 3N MnO2
N = \(\frac{500}{3}\)mL