Consider the following sequence of reactions

\(CH_3CH=CH_2\) \(\overset{Cl_2}{\underset{700K}\longrightarrow}\)A \(\overset{Na_2CO_3}{\underset{420K,12atm}\longrightarrow}\)B \(\overset{(i)\ HOCl}{\underset{(ii)\ NaOH}\longrightarrow}\)C

Compound ‘C’ is

(a)  figure.png

(b) \(\underset{OH}{\underset{|}CH_3}CHCOONa\)

(c) HOCH₂-CH = CH₂

(d) \(\underset{OH}{\underset{|}CH_3}CHCOCl\)