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29/01/2022 4:31 pm
Topic starter
Consider the following reaction
\(H_3C-\underset{D}{\underset{|}C}H-\underset{CH_3}{\underset{|}C}H-CH_3+\dot{Br}\)→ 'X' + HBr
Identify the structure of the major product 'X'
(a) \(H_3C-\underset{D}{\underset{|}C}H-\underset{CH_3}{\underset{|}CH}-\dot{CH_2}\)
(b) \(H_3C-\underset{D}{\underset{|}C}H-\underset{CH_3}{\underset{|}C}-CH_3\)
(c) \(H_3C-\underset{D}{\underset{|}C}-\underset{CH_3}{\underset{|}CH}-CH_3\)
(d) \(H_3C-\dot{C}H-\underset{CH_3}{\underset{|}CH}-CH_3\)
1 Answer
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29/01/2022 4:38 pm
Correct answer: (b) \(H_3C-\underset{D}{\underset{|}C}H-\underset{CH_3}{\underset{|}C}-CH_3\)
Explanation:
\(\dot{Br}\) is less reactive and more selective and so the most stable free radical (3°) will be the major product.