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30/01/2022 3:54 pm
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A compound (X) (C5H8) reacts with ammonical AgNO3 to give a white precipitate, and on oxidation with hot alkaline KMnO4 gives the acid, (CH3)2CHCOOH, therefore X is
(a) CH2 = CH – CH = CH – CH3
(b) CH3 – CH = CH – CH2 – CH3
(c) (CH3)2CH – C ≡ CH
(d) (CH3)2C = C = CH2
1 Answer
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30/01/2022 3:57 pm
Correct answer: (c) (CH3)2CH – C ≡ CH
Explanation:
Compound X reacts with ammonical AgNO3 solution, so it must be a terminal alkyne. Formation of (CH3)2CHCOOH on oxidation of X with hot alkaline KMnO4 further confirms that X is (CH3)2CH ≡ CH.