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# The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 122 m, 22 m and 120 m (see Fig.).

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The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 122 m, 22 m and 120 m (see Fig.). The advertisements yield an earning of ₹5000 per m2 per year. A company hired one of its walls for 3 months. How much rent did it pay?

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The sides of the triangle ABC are 122 m, 22 m and 120 m respectively.

Now, the perimeter will be (122+22+120) = 264 m

Also, the semi perimeter (s) = 264/2 = 132 m

Using Heron’s formula,

Area of the triangle = $$\sqrt{s(s - a)(s - b)(s - c)}$$

= $$\sqrt{132(132 - 122)(132 - 22)(132 - 120)m^2}$$

= $$\sqrt{132 \times 10 \times 110 \times 12 m^2}$$

=1320 m2

We know that the rent of advertising per year = ₹ 5000 per m2

∴ The rent of one wall for 3 months

= Rs. (1320 × 5000 × 3)/12

= Rs 1650000

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