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# Radha made a picture of an aeroplane with coloured paper as shown in Fig. Find the total area of the paper used.

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Radha made a picture of an aeroplane with coloured paper as shown in Fig. Find the total area of the paper used.

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For the triangle I section:

It is an isosceles triangle and the sides are 5 cm, 1 cm and 5 cm

Perimeter = 5 + 5 + 1

= 11 cm

So, semi perimeter = 11/2 cm

= 5.5 cm

Using Heron’s formula,

Area = $$\sqrt{s(s - a)(s - b)(s - c)}$$

= √[5.5(5.5- 5)(5.5-5)(5.5-1)] cm2

= √[5.5×0.5×0.5×4.5] cm2

= 0.75√11 cm2

= 0.75 × 3.317 cm2

= 2.488 cm2 (approx)

This quadrilateral is a rectangle with length and breadth as 6.5 cm and 1 cm respectively.

∴ Area = 6.5 × 1 cm2 = 6.5 cm2

It is a trapezoid with 2 sides as 1 cm each and the third side as 2 cm.

Area of the trapezoid = Area of the parallelogram + Area of the equilateral triangle

The perpendicular height of the parallelogram will be

= $$\sqrt{1^2 - (0.5)^2}$$

= 0.86 cm

And, the area of the equilateral triangle will be (√3/4 × a2) = 0.43

∴ Area of the trapezoid = 0.86 + 0.43

= 1.3 cm(approximately).

For triangle IV and V:

These triangles are 2 congruent right angled triangles having the base as 6 cm and height 1.5 cm

Area triangles IV and V = 2 × (1/2 × 6 × 1.5) cm

= 9 cm2

So, the total area of the paper used = (2.488 + 6.5 + 1.3 + 9) cm

= 19.3 cm2

This post was modified 2 months ago by Samar shah
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