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The mass of a planet is 6 x 10^24 kg and its diameter is 12.8 x 10^3. If the value of gravitational constant be 6.7 x 10^-11 Nm^2/kg^2

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The mass of a planet is 6 x 1024 kg and its diameter is 12.8 x 103. If the value of gravitational constant be 6.7 x 10-11 Nm2/kg2, calculate the value of acceleration due to gravity on the surface of the planet. What planet could this be?

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Acceleration due to gravity,

g = \(G \times \frac{M}{R^2}\)

Mass, M = 6 x 1024 kg

Diameter = 12.8 x 103 km = 12.8 x 106 m

Radius, R = \(\frac{12.8 \times 10^6}{2}\) = 6.4 x 106 m

Gravitational constant, G = 6.7 x 10-11 Nm2/kg2

g = 6.7 x 10-11 x \(\frac{6 \times 10^{24}}{(6.4 \times 10^6)^2}\)

g = \(\frac{6.7 \times 60}{6.4 \times 6.4}\)

g = 9.8 m/s2

As the value of g = 9.8 m/s2, the planet could be Earth.

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