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A stone falls from a building and reaches the ground 2.5 seconds later. How high is the building?

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A stone falls from a building and reaches the ground 2.5 seconds later. How high is the building? (g = 8 m/s2)

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Initial velocity, u = 0 m/s

Acceleration due to gravity, g = 9.8 m/s2

Time taken to reach the ground, t = 2.5 sec

Height, h = ?

Using relation,

s = \(ut + \frac{1}{2}gt^2\)

s = 0 x 2.5 + \(\frac{1}{2}\) x 9.8 x 2.5 x 2.5

s = 0 + 4.9 x 2.5 x 2.5

s = 30.625 m

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