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13/09/2020 8:32 pm
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A solution of CuSO4 is electrolysed for 10 mins. with a current of 1.5 amperes. What is the mass of copper deposited at the cathode?
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13/09/2020 8:35 pm
I = 1.5 Ampere
Time = 10 x 60s = 600s
Q = I x t
= 1.5 x 600 = 900 C
Cu2+ + 2e- → Cu(s)
2F amount of electricity deposit copper = 63.5 g
900 C amount of electricity deposit copper = 63.5 x 900/2 x 96500
= 0.296 g