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03/10/2020 4:59 pm
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Time required to deposit one millimole of aluminium metal by the passage of 9.65 amperes through aqueous solution of aluminium ion is
(a) 30 s
(b) 10 s
(c) 30,000 s
(d) 10,000 s
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03/10/2020 5:04 pm
(a) 30 s
Explanation:
Al3+ + 3e- → Al
1 mole requires = 3 × 96500 coulomb
1 millimole (10–3 mole) requires
= 3 × 96500 × 10–3 C
we know that, Q = i t
or t = Q/t
= (3 x 96500 x 10–3)/9.65
= (3 x 9.65 x 10)/9.65 = 30 s