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The emf of Daniell cell at 298 K is E1 Zn | ZnSO4 (0.01 M) | | CuSO4 (1.0 M) | Cu

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The emf of Daniell cell at 298 K is E1

Zn | ZnSO4 (0.01 M) | | CuSO4 (1.0 M) | Cu

When the concentration of ZnSO4 is 1.0 M and that of CuSO4 is 0.01 M, the emf changed to E2 What is the relation between E1 and E2?

(a) E1 = E2

(b) E2 = 0 ≠ E2

(c) E1 > E2

(d) E1 < E2

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(c) E1 > E2

Explanation:

Using the relation

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