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03/10/2020 5:34 pm
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The charge required for the reduction of 1 mol of MnO-4 to MnO2 is :
(a) 1F
(b) 3F
(c) 5F
(d) 6F
1 Answer
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03/10/2020 5:40 pm
(b) 3F
Explanation:
MnO-4 + 4H+ + 3e- → MnO2 + 2H2O
So, 3F of charge will be required to reduce 1 mole of MnO-4.