Equivalent conductance of an electrolyte containing NaF at infinite dilution is 90.1 Ohm-1cm2. If NaF is replaced by KF what is the value of equivalent conductance? (a) 90.1 Ohm-1cm2 (b) 111.2 Ohm-1cm2 (c) 0 (d) 222.4 Ohm-1cm2

Notifications

Clear all

Equivalent conductance of an electrolyte containing NaF at infinite dilution is 90.1 Ohm^-1cm^2. If NaF is replaced by KF

Electrochemistry

Last Post by Freddie12 5 years ago

1 Posts

2 Users

0 Likes

350 Views

03/10/2020 6:01 pm

Topic starter

Shaneylee18

(@shaneylee18)

Illustrious Member

2184 Posts
2182 0 0

Equivalent conductance of an electrolyte containing NaF at infinite dilution is 90.1 Ohm^-1cm². If NaF is replaced by KF what is the value of equivalent conductance?

(a) 90.1 Ohm^-1cm²

(b) 111.2 Ohm^-1cm²

(d) 222.4 Ohm^-1cm²

Add a comment

Topic Tags

neet electrochemistry

1 Answer

03/10/2020 6:01 pm

Freddie12

(@freddie12)

Noble Member

2094 Posts
0 2094 0

(a) 90.1 Ohm^-1cm²

Explanation:

Because at infinite dilution the equivalent conductance of strong electrolytes furnishing same number of ions is same.

Add a comment

321 Forums
27.3 K Topics
53.8 K Posts
3 Online
12.4 K Members

Forum Icons: Forum contains no unread posts Forum contains unread posts

Topic Icons: Not Replied Replied Active Hot Sticky Unapproved Solved Private Closed

Forum

Equivalent conductance of an electrolyte containing NaF at infinite dilution is 90.1 Ohm^-1cm^2. If NaF is replaced by KF

Super Globals

Options and Features

How Can We Help?

Home

About Us

Contact Us

Privacy Policy

Term of Use

Copyright © 2020 Eanshub

All Rights Reserved