Assertion: For the Daniel cell, Zn|Zn2+ ||Cu2+ Cu with, Ecell = 1.1 V, the application of opposite potential greater than 1.1 V results into flow of electron from cathode to anode.
Reason: Zn is deposited at anode, and Cu is deposited at cathode.
(a) If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
(b) If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
(c) If the Assertion is correct but Reason is incorrect.
(d) If both the Assertion and Reason are incorrect.
(e) If the Assertion is incorrect but the Reason is correct.
(a) If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
Explanation:
In a Daniel cell,
Zn|Zn2+ ||Cu2+ Cu with, Ecell = 1.1 V
The oxidation half cell is
Zn → Zn2+ + 2e-
The reduction half cell is
Cu2+ + 2e-→ Cu
So, Zn + Cu2+ → Zn2+ + Cu
Thus here Zn is oxidised and deposited at anode, and Cu is reduced and deposited at cathode. If the opposite potential is greater than 1.1 V, then electrons flow from cathode to anode. So both A and R are correct.