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20/07/2021 5:34 pm
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What is (a) highest, and (b) lowest, resistance which can be obtained by combining Com resistors having the following resistances?
4 Ω, 8 Ω, 12 Ω, 24 Ω
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20/07/2021 5:38 pm
(a) For obtaining the highest resistance by combining the given resistances, we must connect them in series we get,
R = 4 + 8 + 12 + 24
= 48 ohms
(b) For obtaining the lowest resistance by combining the given resistance, we must connect them in parallel.
we get,
\(\frac{1}{R}\) = \(\frac{1}{4}\) +\(\frac{1}{8}\)+ \(\frac{1}{12}\)
On solving we get,
R = 2 ohms