In the circuit given below :
(a) What is the combined resistance?
(b) What is the p.d. across the combined resistance?
(c) What is the p.d. across the 3 Ω resistor?
(d) What is the current in the 3 Ω resistor?
(e) What is the current in the 6 Ω resistor?
Total current flowing through circuit I = 6 A
R1 = 3 ohm, R2 = 6 ohm
(a) Combined resistance R is
\(\frac{1}{R}\) = \(\frac{1}{3}\) + \(\frac{1}{6}\)
\(\frac{1}{R}\) = \(\frac{3}{6}\)
R = 2 ohms
(b) p.d across the combined resistance = IR = 6 x 2
= 12 V
(c) p.d across the 3 ohm resistor = p.d. across the combined resistance = 12 V
(d) Current flowing through the 3 ohm resistor = \(\frac{V}{R_1}\)
= \(\frac{12}{3}\) = 4 A
(e) Current flowing through the 6 ohm resistor = \(\frac{V}{R_2}\)
= \(\frac{12}{6}\) = 2 A