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18/07/2021 2:15 pm
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In the circuit diagram given below five resistances of 10 Ω, 40 Ω, 30 Ω, 20 Ω and 60 Ω are connected as shown to a 12 V battery.
Calculate :
(a) total resistance in the circuit.
(b) total current flowing in the circuit.
1 Answer
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18/07/2021 2:24 pm
(a) Equivalent resistance of 10Ω and 40 Ω resistances connected in parallel is R1, given as:
\(\frac{1}{R_1}\) = \(\frac{1}{10}\) + \(\frac{1}{40}\) = \(\frac{5}{40}\)
\(R_1 = 8\)Ω
Equivalent resistance of 30Ω, 20Ω and 60 Ω resistances connected in parallel is R1, given as:
\(\frac{1}{R_2}\) = \(\frac{1}{30}\) + \(\frac{1}{20}\) = \(\frac{5}{60}\)
\(R_2 = 8\)Ω
\(R_1\) and \(R_2\) are connected in series,
Total resistance in the circuit is R = \(R_1 + R_2\) = 8 + 10 = 18Ω
(b) Total current flowing in the circuit, I = \(\frac{V}{R}\) = \(\frac{12}{18}\) = 0.67 A