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15/07/2021 1:58 pm
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How many electrons are flowing per second past a point in a circuit in which there is a current of 5 amp?
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15/07/2021 2:01 pm
I = 5A
t = 1s
I = Q/t
Q = I x t
= 5 x 1 = 5 C
No. of electrons comprising 1.6 x 10-19C = 1
No. of electrons comprising 5C
= \(\frac{5}{1.6 \times 10^{-19}}\)
= 31.25 x 1018