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18/07/2021 1:24 pm
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For the circuit shown in the diagram below :
What is the value of :
(i) current through 6 Ωresistor?
(ii) potential difference across 12 Ω resistor?
1 Answer
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18/07/2021 1:32 pm
As per the circuit
V = 4 V
Total resistance in line 1 = R1 = 6 + 3 = 9 ohm
Total resistance in line 2 = R2 = 12 + 3 = 15 ohm
(i) Current through 6Ω resistor = current through line 1 = \(\frac{V}{R_1}\)
= \(\frac{4}{9}\) = 0.44 Ω
(ii) p.d. across line 2 is 4 V
Current through line 2 = \(\frac{V}{R_2}\)
= \(\frac{4}{15}\)Ω
p.d. across 12Ω resistor = \(\frac{4}{15} \times 12\)
= 3.2 V